3w^2-5w=28

Solution for 3w^2-5w=28 equation:

3w^2-5w=28

We move all terms to the left:

3w^2-5w-(28)=0

a = 3; b = -5; c = -28;
Δ = b2-4ac
Δ = -52-4·3·(-28)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-19}{2*3}=\frac{-14}{6}
=-2+1/3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+19}{2*3}=\frac{24}{6}
=4
$